Posted:
SW this is relatively easier :Originally posted by: spashta-waktaNeela, Brilliant answer to the first puzzle by Pooriya!
I am with you and Zoey about the second answer - we can determine the correct switch from 3, not 4 acco. to me.Here's one more:You have a two-scale regular balance with no weights. Weighing just twice, how will you determine the heavier of 8 identical balls? 7 of them have the same weight while 1 is heavy.
pick any 6 balls divide them into the group of 3 each.
- if weigh scale remains same check the rest two and you will find the heavier one.
- otherwise if the balance is tilted then choose 3 from heavier group and pick any two and weigh them, if they are same third one is heavier otherwise its clear.
so you have weighed only two times
- if weigh scale remains same check the rest two and you will find the heavier one.
- otherwise if the balance is tilted then choose 3 from heavier group and pick any two and weigh them, if they are same third one is heavier otherwise its clear.
so you have weighed only two times
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