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{ dPFam awards / S i l v e r Jubilee. } #25 IO (Page 128)

LD-Radha IF-Stunnerz
LD-Radha
LD-Radha

Joined: 12 November 2010
Posts: 25126

Posted: 08 October 2012 at 8:56pm | IP Logged
Vanshu,

see if this helps: http://www.analyzemath.com/calculus/Problems/maximum_volume_problem.html

Its not the same question but it has similar concepts and inequalities.

Im sorry! My brain doesnt really function after 10Ouch


Edited by DilDostiDanceD3 - 08 October 2012 at 8:56pm

The following 1 member(s) liked the above post:

Mohabbateinn

aartipartyy IF-Sizzlerz
aartipartyy
aartipartyy

Joined: 13 April 2012
Posts: 12928

Posted: 08 October 2012 at 8:56pm | IP Logged
ok guys
gonna go to bed now 
GNIGHT!
link me to the next CC when this is over

The following 1 member(s) liked the above post:

VarunKiBiwi

Mohabbateinn IF-Sizzlerz
Mohabbateinn
Mohabbateinn

Joined: 07 January 2012
Posts: 19193

Posted: 08 October 2012 at 8:56pm | IP Logged
Originally posted by DilDostiDanceD3

Originally posted by -Vanshikaa-

an open top box is to be constructed from a rectangular piece of cardboard measuring 52 cm by 36 cm. box is created by cutting congruent corners and then folding up the sides. 

a) express the volume of box as function of x.

b) use the function from part a) to determine value(s) of x, to 2 decimal places, that will result in a volume greater than 3024 cm cubed.

c) determine the dimensions of box for volume given in part b)

myy work so far:

a) let x be the sides being cut off from corners , therefore

p(x) = x(52-2x)(36-2x)

now i dont dont know how to do inequalities part b).. O__0

I get your point now. Let me think about it for a second.

okaay Jasu jee u d besstEmbarrassedEmbarrassed<3 

do you think it wil be like this


x(52-2x)(36-2x) > 3024

then i find zeroes,, and put em on a number line and solve like that ? 

The following 1 member(s) liked the above post:

LD-Radha

LD-Radha IF-Stunnerz
LD-Radha
LD-Radha

Joined: 12 November 2010
Posts: 25126

Posted: 08 October 2012 at 8:57pm | IP Logged
Originally posted by -Vanshikaa-

Originally posted by DilDostiDanceD3

Originally posted by -Vanshikaa-

an open top box is to be constructed from a rectangular piece of cardboard measuring 52 cm by 36 cm. box is created by cutting congruent corners and then folding up the sides. 

a) express the volume of box as function of x.

b) use the function from part a) to determine value(s) of x, to 2 decimal places, that will result in a volume greater than 3024 cm cubed.

c) determine the dimensions of box for volume given in part b)

myy work so far:

a) let x be the sides being cut off from corners , therefore

p(x) = x(52-2x)(36-2x)

now i dont dont know how to do inequalities part b).. O__0

I get your point now. Let me think about it for a second.

okaay Jasu jee u d besstEmbarrassedEmbarrassed<3 

do you think it wil be like this


x(52-2x)(36-2x) > 3024

then i find zeroes,, and put em on a number line and solve like that ? 

OMG VANSHU.

I THINK THATS LEGIT.

OMG.

Try it! 

The following 1 member(s) liked the above post:

Mohabbateinn

MainePyaarKiya IF-Stunnerz

Joined: 23 December 2011
Posts: 37768

Posted: 08 October 2012 at 8:57pm | IP Logged
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The following 1 member(s) liked the above post:

LD-Radha

VarunKiBiwi IF-Sizzlerz
VarunKiBiwi
VarunKiBiwi

Joined: 07 November 2011
Posts: 24261

Posted: 08 October 2012 at 8:57pm | IP Logged
Mohabbateinn IF-Sizzlerz
Mohabbateinn
Mohabbateinn

Joined: 07 January 2012
Posts: 19193

Posted: 08 October 2012 at 8:57pm | IP Logged
Originally posted by DilDostiDanceD3

Vanshu,

see if this helps: http://www.analyzemath.com/calculus/Problems/maximum_volume_problem.html

Its not the same question but it has similar concepts and inequalities.

Im sorry! My brain doesnt really function after 10Ouch

okaaay im reading it noww !! <3 thank UUEmbarrassed noo dont worry, V will figure it out Evil Smile

The following 2 member(s) liked the above post:

LD-RadhaMainePyaarKiya

VarunKiBiwi IF-Sizzlerz
VarunKiBiwi
VarunKiBiwi

Joined: 07 November 2011
Posts: 24261

Posted: 08 October 2012 at 8:58pm | IP Logged
Originally posted by --Aartzz--

ok guys
gonna go to bed now 
GNIGHT!
link me to the next CC when this is over
kay bye love ya tc goodnite barun dreams

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