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Joined: 12 January 2012

Posts: 1

Posted: 12 January 2012 at 2:28am | IP Logged

1. What is the magnitude of g at a height above earth surface where free fall acceleration equals 6.5 m/s*2?

2. Suppose the value of G has just been discovered. Use the value of G and an approximate value for the earth radius(6.38 x 10*g m) to find an approximation fore Earths mass?

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Joined: 30 March 2007

Posts: 5262

Posted: 17 January 2012 at 1:58am | IP Logged
1. g = free fall acceleration = 6.5 m/s^2

2. g = G M/R^2
M = g R^2/G
M = 9.81 * (6.38 * 10^6)^2/(6.67 * 10^-11)
M = 5.99 * 10^24 kg

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